Solving a System of Differential Equations

2x2 System — Substitution with Parameters Variation Method

The Problem

Part A - Find a solution of the homogeneous system with a tα component:
dx/dt = (3/t)x − 4ty
dy/dt = (1/t3)x + (5/t)y
Part B - Using the solution you found, find all solutions of:
dx/dt = (3/t)x − 4ty + 5t3
dy/dt = (1/t3)x + (5/t)y − 4t

Solution Method

A system with variable coefficients. We find a homogeneous solution using a power-of-t ansatz, then use reduction of order (change of variables) to find the general solution of the non-homogeneous system.

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Step 1: Homogeneous Solution - Power Ansatz
Find a solution of the homogeneous system whose components are powers of t

Guiding Question

Try a solution of the form x(t) = atα, y(t) = btβ

Substitute into the system and find α, β and the ratio a:b

Hint: from the equation structure α = β + 2. Try β = 3

x(t) = atα, α = y(t) = btβ, β =
Homogeneous solution: [a, b]T = [ , ]T

Enter integers (any scalar multiple is accepted)

🧐 Digital Friend - Step 1

Step 1 Solution

Ansatz:
x = atα, y = btβ with α = β + 2

The Homogeneous Solution

α = 5, β = 3, [a, b]T = [−2, 1]T
φ(t) = [−2t5, t3]T
Step 2: Change of Variables
Using the homogeneous solution [−2t5, t3]T, define:
x = ξ − 2t5η,   y = t3η
Substitute into the non-homogeneous system and derive scalar equations

Guiding Question

After substitution, two scalar equations are obtained. What are the coefficients?

dξ/dt = (?/t)·ξ − 3t3
dη/dt = t?·ξ − 4t−2

Hint: substitute x = ξ − 2t5η, y = t3η and simplify

dξ/dt = ( /t)·ξ − 3t3
dη/dt = t( )·ξ − 4t−2
🧐 Digital Friend - Step 2

Step 2 Solution

The substitution:
x = ξ − 2t5η,   y = t3η

The Scalar Equations

dξ/dt = (5/t)ξ − 3t3
dη/dt = t−6ξ − 4t−2
Step 3: Solving the ξ Equation
Solve the first-order linear equation:
dξ/dt − (5/t)ξ = −3t3

Guiding Question

Find an integrating factor and solve. The solution has the form ξ = c1t4 + At5

μ = e−∫(5/t)dt = t−5

Hint: multiply by the integrating factor and integrate

c1 =
🧐 Digital Friend - Step 3

Step 3 Solution

The equation:
dξ/dt − (5/t)ξ = −3t3
Integrating factor:
μ = t−5

The Solution

ξ = 3t4 + At5
Step 4: Solving the η Equation
Substitute ξ = 3t4 + At5 into the equation:
dη/dt = t−6ξ − 4t−2

Guiding Question

Simplify and integrate. The solution has the form η = c2t−1 + A·ln(t) + B

dη/dt = −t−2 + At−1

Hint: integrate term by term

c2 =
🧐 Digital Friend - Step 4

Step 4 Solution

Substituting ξ:
dη/dt = t−6(3t4 + At5) − 4t−2 = −t−2 + At−1
Integration:
η = t−1 + A·ln(t) + B

The Solution

η = t−1 + A·ln(t) + B
Step 5: The General Solution
Substitute back x = ξ − 2t5η, y = t3η
Find the particular solution (without constants A and B)

Guiding Question

Substitute ξ = 3t4 + At5 and η = t−1 + A·ln(t) + B

xp(t) = t?,   yp(t) = t?

Hint: the particular solution is obtained when A = B = 0

xp(t) = t( ) yp(t) = t( )
🧐 Digital Friend - Step 5

Step 5 Solution

Back-substitution (A=B=0):
x = ξ − 2t5η = 3t4 − 2t5·t−1 = 3t4 − 2t4 = t4
y component:
y = t3η = t3·t−1 = t2

The Particular Solution

xp(t) = t4,   yp(t) = t2