Given the ODE
the surface \( f(x,y) = y - x \) describes a plane.
The level curves of this plane are the lines
On each isocline of height \( C \) we draw vectors whose slope is \( C \):
For \( C = 2 \) we get \( y = x + 2 \). On this line we draw vectors with direction \( \arctan(2) \approx 63^\circ \).
For \( C = 1 \) we get \( y = x + 1 \). On this line we draw vectors with direction \( \arctan(1) = 45^\circ \).
For \( C = 0 \) we get \( y = x \). On this line we draw vectors with direction \( \arctan(0) = 0^\circ \).
For \( C = -1 \) we get \( y = x - 1 \). On this line we draw vectors with direction \( \arctan(-1) = -45^\circ \).
Continuing this way we obtain the dense direction field. Note that the vectors of the same isocline all point in the same direction. That direction is \( \arctan C \), where \( C \) is the height of the isocline on the surface \( f(x,y) = y - x \).
Every solution of the ODE must advance so that it is always tangent to the direction field. The panel shows the solutions obtained for